p^2+3p=70

Solution for p^2+3p=70 equation:

p^2+3p=70

We move all terms to the left:

p^2+3p-(70)=0

a = 1; b = 3; c = -70;
Δ = b2-4ac
Δ = 32-4·1·(-70)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-17}{2*1}=\frac{-20}{2}
=-10
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+17}{2*1}=\frac{14}{2}
=7
$